A
anoopjose
Guest
Kokie yra 3 dB Bandwidth perdavimo funkcijų S / (s ² + kaip + B) ir 1 / (s ² + kaip + b)?
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M
Mansour_M
Guest
Hi dear anoopjose! Prisiimti d = sqrt (2). Taigi: *********************************************** Pirmasis: 1 / (s ² + kaip + b) = 1/sqrt (2) = 1 / d S1 = -1 / 2 * +1 / 2 * (a ^ 2-4 * B 4 *, c) ^ (1 / 2) S2 = -1 / 2 * 1 / 2 * (a ^ 2-4 * B 4 *, c) ^ (1 / 2) ************* ********************************** Antrasis: S / (s ² + kaip + b) = 1 / sqrt (2) = 1 / d S1 = -1 / 2 * +1 / 2 * d +1 / 2 * (a ^ 2-2 * a * d + d ^ 2-4 * b) ^ (1 / 2) S2 = -1 / 2 * +1 / 2 * d-1 / 2 * (a ^ 2-2 * a * d + d ^ 2-4 * b) ^ (1 / 2) **** ******************************************* Ačiū!
D
demodb
Guest
manote, kad jums reikia apskaičiuoti polių, kuris yra atliekamas nustatant skaitiklis lygus nuliui.
K
Kral
Guest
anoopjose, Pakaitinio s = ks. Nustatykite rezultatas = 1 / [sqrt (2)]. Pirmame pavyzdyje, jūs wil gauti dvi reikšmes, W. Antrajame pavyzdyje, jūs gausite 1 vertę. , Kral