F
fighter5555
Guest
Tai galima gauti Trigonometrinis serijos kompleksas Furjė eilutė
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A
aboozar.hamidipoor
Guest
Aišku, kad galima lengvai Oilerio tapatybė.
M
mayyan
Guest
Taip jos posible.Pačios matematiniai knygų forier analizę ji įrodymas.Jei Jūs vis dar cant find it let me know ir aš po to.
maayan
maayan
F
fighter5555
Guest
mayyan galite pls post tirpalui
thks
thks
D
DrDolittle
Guest
pakaitalas cos Φ = E (iΦ) e (-iΦ) / 2
sin Φ = E (iΦ) - e (-iΦ) / 2
Linkėjimai
drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
sin Φ = E (iΦ) - e (-iΦ) / 2
Linkėjimai
drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
B
baluba
Guest
DrDolittle rašė:
pakaitalas cos Φ = E (iΦ) e (-iΦ) / 2
sin Φ = E (iΦ) - e (-iΦ) / 2Linkėjimai
drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
pakaitalas cos Φ = E (iΦ) e (-iΦ) / 2
sin Φ = E (iΦ) - e (-iΦ) / 2Linkėjimai
drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
D
DrDolittle
Guest
Oh yeah, thanx už šią pastabą.Aš pamiršau pridėti, kad aš veiksnys.
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drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
Linkėjimai
drdolittle
<img src="http://www.edaboard.com/images/smiles/icon_smile.gif" alt="Šypsotis" border="0" />
T
tara1
Guest
h ** p: / / satyap.csoft.net / ss.pdf